-4b-3=10+5(-b-1)

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Solution for -4b-3=10+5(-b-1) equation: 



-4b-3=10+5(-b-1)

We move all terms to the left:

-4b-3-(10+5(-b-1))=0

We add all the numbers together, and all the variables

-4b-(10+5(-1b-1))-3=0



We calculate terms in parentheses: -(10+5(-1b-1)), so:

10+5(-1b-1)

determiningTheFunctionDomain
5(-1b-1)+10

We multiply parentheses

-5b-5+10

We add all the numbers together, and all the variables

-5b+5

Back to the equation:

-(-5b+5)



We get rid of parentheses

-4b+5b-5-3=0

We add all the numbers together, and all the variables

b-8=0

We move all terms containing b to the left, all other terms to the right

b=8

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