-44-10x=-7x(x+8)

Solution for -44-10x=-7x(x+8) equation:

-44-10x=-7x(x+8)

We move all terms to the left:

-44-10x-(-7x(x+8))=0


We calculate terms in parentheses: -(-7x(x+8)), so:

-7x(x+8)

We multiply parentheses

-7x^2-56x

Back to the equation:

-(-7x^2-56x)


We get rid of parentheses

7x^2+56x-10x-44=0

We add all the numbers together, and all the variables

7x^2+46x-44=0

a = 7; b = 46; c = -44;
Δ = b2-4ac
Δ = 462-4·7·(-44)
Δ = 3348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3348}=\sqrt{36*93}=\sqrt{36}*\sqrt{93}=6\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-6\sqrt{93}}{2*7}=\frac{-46-6\sqrt{93}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+6\sqrt{93}}{2*7}=\frac{-46+6\sqrt{93}}{14}
$