-44+4y+3=2(5y-2)-7

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Solution for -44+4y+3=2(5y-2)-7 equation: 



-44+4y+3=2(5y-2)-7

We move all terms to the left:

-44+4y+3-(2(5y-2)-7)=0

We add all the numbers together, and all the variables

4y-(2(5y-2)-7)-41=0



We calculate terms in parentheses: -(2(5y-2)-7), so:

2(5y-2)-7

We multiply parentheses

10y-4-7

We add all the numbers together, and all the variables

10y-11

Back to the equation:

-(10y-11)



We get rid of parentheses

4y-10y+11-41=0

We add all the numbers together, and all the variables

-6y-30=0

We move all terms containing y to the left, all other terms to the right

-6y=30

y=30/-6

y=-5

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