-41+12y+3=3(5y-3)-2

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Solution for -41+12y+3=3(5y-3)-2 equation: 



-41+12y+3=3(5y-3)-2

We move all terms to the left:

-41+12y+3-(3(5y-3)-2)=0

We add all the numbers together, and all the variables

12y-(3(5y-3)-2)-38=0



We calculate terms in parentheses: -(3(5y-3)-2), so:

3(5y-3)-2

We multiply parentheses

15y-9-2

We add all the numbers together, and all the variables

15y-11

Back to the equation:

-(15y-11)



We get rid of parentheses

12y-15y+11-38=0

We add all the numbers together, and all the variables

-3y-27=0

We move all terms containing y to the left, all other terms to the right

-3y=27

y=27/-3

y=-9

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