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-40=5-9(v-5)
We move all terms to the left:
-40-(5-9(v-5))=0
We calculate terms in parentheses: -(5-9(v-5)), so:We get rid of parentheses
5-9(v-5)
determiningTheFunctionDomain -9(v-5)+5
We multiply parentheses
-9v+45+5
We add all the numbers together, and all the variables
-9v+50
Back to the equation:
-(-9v+50)
9v-50-40=0
We add all the numbers together, and all the variables
9v-90=0
We move all terms containing v to the left, all other terms to the right
9v=90
v=90/9
v=10
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