-40=4(8+3x)+2(7x-2)

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Solution for -40=4(8+3x)+2(7x-2) equation: 



-40=4(8+3x)+2(7x-2)

We move all terms to the left:

-40-(4(8+3x)+2(7x-2))=0

We add all the numbers together, and all the variables

-(4(3x+8)+2(7x-2))-40=0



We calculate terms in parentheses: -(4(3x+8)+2(7x-2)), so:

4(3x+8)+2(7x-2)

We multiply parentheses

12x+14x+32-4

We add all the numbers together, and all the variables

26x+28

Back to the equation:

-(26x+28)



We get rid of parentheses

-26x-28-40=0

We add all the numbers together, and all the variables

-26x-68=0

We move all terms containing x to the left, all other terms to the right

-26x=68

x=68/-26

x=-2+8/13

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