-40+8a=4(a-3)+8a

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Solution for -40+8a=4(a-3)+8a equation:



-40+8a=4(a-3)+8a
We move all terms to the left:
-40+8a-(4(a-3)+8a)=0
We calculate terms in parentheses: -(4(a-3)+8a), so:
4(a-3)+8a
We add all the numbers together, and all the variables
8a+4(a-3)
We multiply parentheses
8a+4a-12
We add all the numbers together, and all the variables
12a-12
Back to the equation:
-(12a-12)
We get rid of parentheses
8a-12a+12-40=0
We add all the numbers together, and all the variables
-4a-28=0
We move all terms containing a to the left, all other terms to the right
-4a=28
a=28/-4
a=-7

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