-40(8y+5)-28(-7y-6)=128y-907

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Solution for -40(8y+5)-28(-7y-6)=128y-907 equation: 



-40(8y+5)-28(-7y-6)=128y-907

We move all terms to the left:

-40(8y+5)-28(-7y-6)-(128y-907)=0

We multiply parentheses

-320y+196y-(128y-907)-200+168=0

We get rid of parentheses

-320y+196y-128y+907-200+168=0

We add all the numbers together, and all the variables

-252y+875=0

We move all terms containing y to the left, all other terms to the right

-252y=-875

y=-875/-252

y=3+17/36

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