-40(-d-5)=20(2d+10)

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Solution for -40(-d-5)=20(2d+10) equation:



-40(-d-5)=20(2d+10)
We move all terms to the left:
-40(-d-5)-(20(2d+10))=0
We add all the numbers together, and all the variables
-40(-1d-5)-(20(2d+10))=0
We multiply parentheses
40d-(20(2d+10))+200=0
We calculate terms in parentheses: -(20(2d+10)), so:
20(2d+10)
We multiply parentheses
40d+200
Back to the equation:
-(40d+200)
We get rid of parentheses
40d-40d-200+200=0
We add all the numbers together, and all the variables
=0
d=0/1
d=0

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