-4/a+3=a/2

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Solution for -4/a+3=a/2 equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

3-4/a = a/2 // - a/2

3-(a/2)-4/a = 0

3*a^0-1/2*a^1-4*a^-1 = 0

(3*a^1-1/2*a^2-4*a^0)/(a^1) = 0 // * a^2

a^1*(3*a^1-1/2*a^2-4*a^0) = 0

a^1

(-1/2)*a^2+3*a-4 = 0

(-1/2)*a^2+3*a-4 = 0

DELTA = 3^2-(-4*4*(-1/2))

DELTA = 1

DELTA > 0

a = (1^(1/2)-3)/(2*(-1/2)) or a = (-1^(1/2)-3)/(2*(-1/2))

a = 2 or a = 4

a in { 2, 4} 

a in { 2, 4 }

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