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-4/5w+1/4=1-5+1/3w
We move all terms to the left:
-4/5w+1/4-(1-5+1/3w)=0
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
Domain of the equation: 3w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
-4/5w-(1/3w-4)+1/4=0
We get rid of parentheses
-4/5w-1/3w+4+1/4=0
We calculate fractions
45w^2/240w^2+(-192w)/240w^2+(-80w)/240w^2+4=0
We multiply all the terms by the denominator
45w^2+(-192w)+(-80w)+4*240w^2=0
Wy multiply elements
45w^2+960w^2+(-192w)+(-80w)=0
We get rid of parentheses
45w^2+960w^2-192w-80w=0
We add all the numbers together, and all the variables
1005w^2-272w=0
a = 1005; b = -272; c = 0;
Δ = b2-4ac
Δ = -2722-4·1005·0
Δ = 73984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{73984}=272$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-272)-272}{2*1005}=\frac{0}{2010} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-272)+272}{2*1005}=\frac{544}{2010} =272/1005 $
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