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-4/5t=2/5=2/3
We move all terms to the left:
-4/5t-(2/5)=0
Domain of the equation: 5t!=0We add all the numbers together, and all the variables
t!=0/5
t!=0
t∈R
-4/5t-(+2/5)=0
We get rid of parentheses
-4/5t-2/5=0
We calculate fractions
=0
t=0/1
t=0
Równanie nie ma rozwiązania
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