-4/5(-y+10)-1/3(y+2)=1/3

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Solution for -4/5(-y+10)-1/3(y+2)=1/3 equation: 



-4/5(-y+10)-1/3(y+2)=1/3

We move all terms to the left:

-4/5(-y+10)-1/3(y+2)-(1/3)=0



Domain of the equation: 5(-y+10)!=0

y∈R





Domain of the equation: 3(y+2)!=0

y∈R



We add all the numbers together, and all the variables

-4/5(-1y+10)-1/3(y+2)-(+1/3)=0

We get rid of parentheses

-4/5(-1y+10)-1/3(y+2)-1/3=0

We calculate fractions


(-36yy/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3)=0



We calculate terms in parentheses: +(-36yy/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3), so:

-36yy/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3)+(-5y(-)/(5(-1y+10)*3(y+2)*3

We can not solve this equation

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