-4-2(3x-2)=5-(2x-3)-3

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Solution for -4-2(3x-2)=5-(2x-3)-3 equation: 



-4-2(3x-2)=5-(2x-3)-3

We move all terms to the left:

-4-2(3x-2)-(5-(2x-3)-3)=0

We multiply parentheses

-6x-(5-(2x-3)-3)+4-4=0



We calculate terms in parentheses: -(5-(2x-3)-3), so:

5-(2x-3)-3

determiningTheFunctionDomain
-(2x-3)+5-3

We add all the numbers together, and all the variables

-(2x-3)+2

We get rid of parentheses

-2x+3+2

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We add all the numbers together, and all the variables

-6x-(-2x+5)=0

We get rid of parentheses

-6x+2x-5=0

We add all the numbers together, and all the variables

-4x-5=0

We move all terms containing x to the left, all other terms to the right

-4x=5

x=5/-4

x=-1+1/4

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