-4+6x+20+3x=10(x+1)+6

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Solution for -4+6x+20+3x=10(x+1)+6 equation: 



-4+6x+20+3x=10(x+1)+6

We move all terms to the left:

-4+6x+20+3x-(10(x+1)+6)=0

We add all the numbers together, and all the variables

9x-(10(x+1)+6)+16=0



We calculate terms in parentheses: -(10(x+1)+6), so:

10(x+1)+6

We multiply parentheses

10x+10+6

We add all the numbers together, and all the variables

10x+16

Back to the equation:

-(10x+16)



We get rid of parentheses

9x-10x-16+16=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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