-4+3x-8=2(x-5)+x-2

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Solution for -4+3x-8=2(x-5)+x-2 equation: 



-4+3x-8=2(x-5)+x-2

We move all terms to the left:

-4+3x-8-(2(x-5)+x-2)=0

We add all the numbers together, and all the variables

3x-(2(x-5)+x-2)-12=0



We calculate terms in parentheses: -(2(x-5)+x-2), so:

2(x-5)+x-2

We add all the numbers together, and all the variables

x+2(x-5)-2

We multiply parentheses

x+2x-10-2

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

3x-3x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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