-4+2c=3(2c+4)

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Solution for -4+2c=3(2c+4) equation: 



-4+2c=3(2c+4)

We move all terms to the left:

-4+2c-(3(2c+4))=0



We calculate terms in parentheses: -(3(2c+4)), so:

3(2c+4)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

2c-6c-12-4=0

We add all the numbers together, and all the variables

-4c-16=0

We move all terms containing c to the left, all other terms to the right

-4c=16

c=16/-4

c=-4

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