-4+2(-3v+5)=2+2(-2v-1)

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Solution for -4+2(-3v+5)=2+2(-2v-1) equation: 



-4+2(-3v+5)=2+2(-2v-1)

We move all terms to the left:

-4+2(-3v+5)-(2+2(-2v-1))=0

We multiply parentheses

-6v-(2+2(-2v-1))+10-4=0



We calculate terms in parentheses: -(2+2(-2v-1)), so:

2+2(-2v-1)

determiningTheFunctionDomain
2(-2v-1)+2

We multiply parentheses

-4v-2+2

We add all the numbers together, and all the variables

-4v

Back to the equation:

-(-4v)



We add all the numbers together, and all the variables

-6v-(-4v)+6=0

We get rid of parentheses

-6v+4v+6=0

We add all the numbers together, and all the variables

-2v+6=0

We move all terms containing v to the left, all other terms to the right

-2v=-6

v=-6/-2

v=+3

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