-4+133=7(7-2c)-2c

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Solution for -4+133=7(7-2c)-2c equation: 



-4+133=7(7-2c)-2c

We move all terms to the left:

-4+133-(7(7-2c)-2c)=0

We add all the numbers together, and all the variables

-(7(-2c+7)-2c)-4+133=0

We add all the numbers together, and all the variables

-(7(-2c+7)-2c)+129=0



We calculate terms in parentheses: -(7(-2c+7)-2c), so:

7(-2c+7)-2c

We add all the numbers together, and all the variables

-2c+7(-2c+7)

We multiply parentheses

-2c-14c+49

We add all the numbers together, and all the variables

-16c+49

Back to the equation:

-(-16c+49)



We get rid of parentheses

16c-49+129=0

We add all the numbers together, and all the variables

16c+80=0

We move all terms containing c to the left, all other terms to the right

16c=-80

c=-80/16

c=-5

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