-4(z-5)-z=-5(z+3)+35

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Solution for -4(z-5)-z=-5(z+3)+35 equation: 


Simplifying
-4(z + -5) + -1z = -5(z + 3) + 35

Reorder the terms:
-4(-5 + z) + -1z = -5(z + 3) + 35
(-5 * -4 + z * -4) + -1z = -5(z + 3) + 35
(20 + -4z) + -1z = -5(z + 3) + 35

Combine like terms: -4z + -1z = -5z
20 + -5z = -5(z + 3) + 35

Reorder the terms:
20 + -5z = -5(3 + z) + 35
20 + -5z = (3 * -5 + z * -5) + 35
20 + -5z = (-15 + -5z) + 35

Reorder the terms:
20 + -5z = -15 + 35 + -5z

Combine like terms: -15 + 35 = 20
20 + -5z = 20 + -5z

Add '-20' to each side of the equation.
20 + -20 + -5z = 20 + -20 + -5z

Combine like terms: 20 + -20 = 0
0 + -5z = 20 + -20 + -5z
-5z = 20 + -20 + -5z

Combine like terms: 20 + -20 = 0
-5z = 0 + -5z
-5z = -5z

Add '5z' to each side of the equation.
-5z + 5z = -5z + 5z

Combine like terms: -5z + 5z = 0
0 = -5z + 5z

Combine like terms: -5z + 5z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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