-4(y-3)=-8y+4

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Solution for -4(y-3)=-8y+4 equation: 



-4(y-3)=-8y+4

We move all terms to the left:

-4(y-3)-(-8y+4)=0

We multiply parentheses

-4y-(-8y+4)+12=0

We get rid of parentheses

-4y+8y-4+12=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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