-4(y+3)+y=2(1-2y)-6

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Solution for -4(y+3)+y=2(1-2y)-6 equation: 



-4(y+3)+y=2(1-2y)-6

We move all terms to the left:

-4(y+3)+y-(2(1-2y)-6)=0

We add all the numbers together, and all the variables

-4(y+3)+y-(2(-2y+1)-6)=0

We add all the numbers together, and all the variables

y-4(y+3)-(2(-2y+1)-6)=0

We multiply parentheses

y-4y-(2(-2y+1)-6)-12=0



We calculate terms in parentheses: -(2(-2y+1)-6), so:

2(-2y+1)-6

We multiply parentheses

-4y+2-6

We add all the numbers together, and all the variables

-4y-4

Back to the equation:

-(-4y-4)



We add all the numbers together, and all the variables

-3y-(-4y-4)-12=0

We get rid of parentheses

-3y+4y+4-12=0

We add all the numbers together, and all the variables

y-8=0

We move all terms containing y to the left, all other terms to the right

y=8

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