-4(x-4)+x=-3(3x+2)+4

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Solution for -4(x-4)+x=-3(3x+2)+4 equation: 



-4(x-4)+x=-3(3x+2)+4

We move all terms to the left:

-4(x-4)+x-(-3(3x+2)+4)=0

We add all the numbers together, and all the variables

x-4(x-4)-(-3(3x+2)+4)=0

We multiply parentheses

x-4x-(-3(3x+2)+4)+16=0



We calculate terms in parentheses: -(-3(3x+2)+4), so:

-3(3x+2)+4

We multiply parentheses

-9x-6+4

We add all the numbers together, and all the variables

-9x-2

Back to the equation:

-(-9x-2)



We add all the numbers together, and all the variables

-3x-(-9x-2)+16=0

We get rid of parentheses

-3x+9x+2+16=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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