-4(x-3)=8(2-1/4x)

Solution for -4(x-3)=8(2-1/4x) equation:

-4(x-3)=8(2-1/4x)

We move all terms to the left:

-4(x-3)-(8(2-1/4x))=0


Domain of the equation: 4x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-4(x-3)-(8(-1/4x+2))=0

We multiply parentheses

-4x-(8(-1/4x+2))+12=0

We multiply all the terms by the denominator


-4x*4x+12*4x-1+2))-(8(+2))=0

We add all the numbers together, and all the variables

-4x*4x+12*4x-1+2))-(82)=0

We add all the numbers together, and all the variables

-4x*4x+12*4x=0

Wy multiply elements

-16x^2+48x=0

a = -16; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-16)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-16}=\frac{-96}{-32}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-16}=\frac{0}{-32}
=0
$