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-4(x+8)+23x(x=2)
We move all terms to the left:
-4(x+8)+23x(x-(2))=0
We multiply parentheses
23x^2-4x-46x-32=0
We add all the numbers together, and all the variables
23x^2-50x-32=0
a = 23; b = -50; c = -32;
Δ = b2-4ac
Δ = -502-4·23·(-32)
Δ = 5444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5444}=\sqrt{4*1361}=\sqrt{4}*\sqrt{1361}=2\sqrt{1361}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1361}}{2*23}=\frac{50-2\sqrt{1361}}{46} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1361}}{2*23}=\frac{50+2\sqrt{1361}}{46} $
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