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-4(x)=1/2x+5
We move all terms to the left:
-4(x)-(1/2x+5)=0
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
-4x-1/2x-5=0
We multiply all the terms by the denominator
-4x*2x-5*2x-1=0
Wy multiply elements
-8x^2-10x-1=0
a = -8; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·(-8)·(-1)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{17}}{2*-8}=\frac{10-2\sqrt{17}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{17}}{2*-8}=\frac{10+2\sqrt{17}}{-16} $
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