-4(v+1)=v-2+2(2v+2)

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Solution for -4(v+1)=v-2+2(2v+2) equation: 



-4(v+1)=v-2+2(2v+2)

We move all terms to the left:

-4(v+1)-(v-2+2(2v+2))=0

We multiply parentheses

-4v-(v-2+2(2v+2))-4=0



We calculate terms in parentheses: -(v-2+2(2v+2)), so:

v-2+2(2v+2)

determiningTheFunctionDomain
v+2(2v+2)-2

We multiply parentheses

v+4v+4-2

We add all the numbers together, and all the variables

5v+2

Back to the equation:

-(5v+2)



We get rid of parentheses

-4v-5v-2-4=0

We add all the numbers together, and all the variables

-9v-6=0

We move all terms containing v to the left, all other terms to the right

-9v=6

v=6/-9

v=-2/3

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