-4(t-3)-(t+2)=10

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Solution for -4(t-3)-(t+2)=10 equation: 



-4(t-3)-(t+2)=10

We move all terms to the left:

-4(t-3)-(t+2)-(10)=0

We multiply parentheses

-4t-(t+2)+12-10=0

We get rid of parentheses

-4t-t-2+12-10=0

We add all the numbers together, and all the variables

-5t=0

t=0/-5

t=0

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