-4(n-2)+2n=20+2n

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Solution for -4(n-2)+2n=20+2n equation:



-4(n-2)+2n=20+2n
We move all terms to the left:
-4(n-2)+2n-(20+2n)=0
We add all the numbers together, and all the variables
-4(n-2)+2n-(2n+20)=0
We add all the numbers together, and all the variables
2n-4(n-2)-(2n+20)=0
We multiply parentheses
2n-4n-(2n+20)+8=0
We get rid of parentheses
2n-4n-2n-20+8=0
We add all the numbers together, and all the variables
-4n-12=0
We move all terms containing n to the left, all other terms to the right
-4n=12
n=12/-4
n=-3

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