-4(k-3)+13=3k+12

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Solution for -4(k-3)+13=3k+12 equation: 



-4(k-3)+13=3k+12

We move all terms to the left:

-4(k-3)+13-(3k+12)=0

We multiply parentheses

-4k-(3k+12)+12+13=0

We get rid of parentheses

-4k-3k-12+12+13=0

We add all the numbers together, and all the variables

-7k+13=0

We move all terms containing k to the left, all other terms to the right

-7k=-13

k=-13/-7

k=1+6/7

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