-4(k+2)-k-5=5(k+4)+7

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Solution for -4(k+2)-k-5=5(k+4)+7 equation: 



-4(k+2)-k-5=5(k+4)+7

We move all terms to the left:

-4(k+2)-k-5-(5(k+4)+7)=0

We add all the numbers together, and all the variables

-1k-4(k+2)-(5(k+4)+7)-5=0

We multiply parentheses

-1k-4k-(5(k+4)+7)-8-5=0



We calculate terms in parentheses: -(5(k+4)+7), so:

5(k+4)+7

We multiply parentheses

5k+20+7

We add all the numbers together, and all the variables

5k+27

Back to the equation:

-(5k+27)



We add all the numbers together, and all the variables

-5k-(5k+27)-13=0

We get rid of parentheses

-5k-5k-27-13=0

We add all the numbers together, and all the variables

-10k-40=0

We move all terms containing k to the left, all other terms to the right

-10k=40

k=40/-10

k=-4

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