-4(d+2)-d-5=(d+4)+7

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Solution for -4(d+2)-d-5=(d+4)+7 equation: 



-4(d+2)-d-5=(d+4)+7

We move all terms to the left:

-4(d+2)-d-5-((d+4)+7)=0

We add all the numbers together, and all the variables

-1d-4(d+2)-((d+4)+7)-5=0

We multiply parentheses

-1d-4d-((d+4)+7)-8-5=0



We calculate terms in parentheses: -((d+4)+7), so:

(d+4)+7

We get rid of parentheses

d+4+7

We add all the numbers together, and all the variables

d+11

Back to the equation:

-(d+11)



We add all the numbers together, and all the variables

-5d-(d+11)-13=0

We get rid of parentheses

-5d-d-11-13=0

We add all the numbers together, and all the variables

-6d-24=0

We move all terms containing d to the left, all other terms to the right

-6d=24

d=24/-6

d=-4

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