-4(b-3)=-28+6b

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Solution for -4(b-3)=-28+6b equation: 



-4(b-3)=-28+6b

We move all terms to the left:

-4(b-3)-(-28+6b)=0

We add all the numbers together, and all the variables

-4(b-3)-(6b-28)=0

We multiply parentheses

-4b-(6b-28)+12=0

We get rid of parentheses

-4b-6b+28+12=0

We add all the numbers together, and all the variables

-10b+40=0

We move all terms containing b to the left, all other terms to the right

-10b=-40

b=-40/-10

b=+4

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