-4(b+1)+2b=3b-1

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Solution for -4(b+1)+2b=3b-1 equation: 



-4(b+1)+2b=3b-1

We move all terms to the left:

-4(b+1)+2b-(3b-1)=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3b-1)=0

We multiply parentheses

2b-4b-(3b-1)-4=0

We get rid of parentheses

2b-4b-3b+1-4=0

We add all the numbers together, and all the variables

-5b-3=0

We move all terms containing b to the left, all other terms to the right

-5b=3

b=3/-5

b=-3/5

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