-4(b+1)+2b=(2b-1)

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Solution for -4(b+1)+2b=(2b-1) equation: 



-4(b+1)+2b=(2b-1)

We move all terms to the left:

-4(b+1)+2b-((2b-1))=0

We add all the numbers together, and all the variables

2b-4(b+1)-((2b-1))=0

We multiply parentheses

2b-4b-((2b-1))-4=0



We calculate terms in parentheses: -((2b-1)), so:

(2b-1)

We get rid of parentheses

2b-1

Back to the equation:

-(2b-1)



We add all the numbers together, and all the variables

-2b-(2b-1)-4=0

We get rid of parentheses

-2b-2b+1-4=0

We add all the numbers together, and all the variables

-4b-3=0

We move all terms containing b to the left, all other terms to the right

-4b=3

b=3/-4

b=-3/4

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