-4(6+m)=1/2(-4m-48)-2m

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Solution for -4(6+m)=1/2(-4m-48)-2m equation: 



-4(6+m)=1/2(-4m-48)-2m

We move all terms to the left:

-4(6+m)-(1/2(-4m-48)-2m)=0



Domain of the equation: 2(-4m-48)-2m)!=0

m∈R



We add all the numbers together, and all the variables

-4(m+6)-(1/2(-4m-48)-2m)=0

We multiply parentheses

-4m-(1/2(-4m-48)-2m)-24=0

We multiply all the terms by the denominator


-4m*2(-4m-48)-2m)-(1-24*2(-4m-48)-2m)=0

Wy multiply elements

-8m^2(--2m)-(1-48m(--2m)=0



We calculate terms in parentheses: -(1-48m(--2m), so:

1-48m(--2m

determiningTheFunctionDomain
-48m(--2m+1

We use the square of the difference formula

-48m(+2m+1

Back to the equation:

-(-48m(+2m+1)



We add all the numbers together, and all the variables

-8m^2(-2m)-(-48m(2m+1)=0



We calculate terms in parentheses: -(-48m(2m+1), so:

-48m(2m+1





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-48m(2m+1





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-48m(2m+1





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-48m(2m+1





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-48m(2m+1





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-48m(2m+1





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