-4(5y-5)-y=4(y-2)

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Solution for -4(5y-5)-y=4(y-2) equation: 



-4(5y-5)-y=4(y-2)

We move all terms to the left:

-4(5y-5)-y-(4(y-2))=0

We add all the numbers together, and all the variables

-1y-4(5y-5)-(4(y-2))=0

We multiply parentheses

-1y-20y-(4(y-2))+20=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We add all the numbers together, and all the variables

-21y-(4y-8)+20=0

We get rid of parentheses

-21y-4y+8+20=0

We add all the numbers together, and all the variables

-25y+28=0

We move all terms containing y to the left, all other terms to the right

-25y=-28

y=-28/-25

y=1+3/25

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