-4(4y+3)-19=-8(y+5)+4y

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Solution for -4(4y+3)-19=-8(y+5)+4y equation: 



-4(4y+3)-19=-8(y+5)+4y

We move all terms to the left:

-4(4y+3)-19-(-8(y+5)+4y)=0

We multiply parentheses

-16y-(-8(y+5)+4y)-12-19=0



We calculate terms in parentheses: -(-8(y+5)+4y), so:

-8(y+5)+4y

We add all the numbers together, and all the variables

4y-8(y+5)

We multiply parentheses

4y-8y-40

We add all the numbers together, and all the variables

-4y-40

Back to the equation:

-(-4y-40)



We add all the numbers together, and all the variables

-16y-(-4y-40)-31=0

We get rid of parentheses

-16y+4y+40-31=0

We add all the numbers together, and all the variables

-12y+9=0

We move all terms containing y to the left, all other terms to the right

-12y=-9

y=-9/-12

y=3/4

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