-4(4t-5)+4=-2(2t-8)-10

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Solution for -4(4t-5)+4=-2(2t-8)-10 equation: 



-4(4t-5)+4=-2(2t-8)-10

We move all terms to the left:

-4(4t-5)+4-(-2(2t-8)-10)=0

We multiply parentheses

-16t-(-2(2t-8)-10)+20+4=0



We calculate terms in parentheses: -(-2(2t-8)-10), so:

-2(2t-8)-10

We multiply parentheses

-4t+16-10

We add all the numbers together, and all the variables

-4t+6

Back to the equation:

-(-4t+6)



We add all the numbers together, and all the variables

-16t-(-4t+6)+24=0

We get rid of parentheses

-16t+4t-6+24=0

We add all the numbers together, and all the variables

-12t+18=0

We move all terms containing t to the left, all other terms to the right

-12t=-18

t=-18/-12

t=1+1/2

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