-4(3y-5)+6y=2(y+5)

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Solution for -4(3y-5)+6y=2(y+5) equation: 



-4(3y-5)+6y=2(y+5)

We move all terms to the left:

-4(3y-5)+6y-(2(y+5))=0

We add all the numbers together, and all the variables

6y-4(3y-5)-(2(y+5))=0

We multiply parentheses

6y-12y-(2(y+5))+20=0



We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)



We add all the numbers together, and all the variables

-6y-(2y+10)+20=0

We get rid of parentheses

-6y-2y-10+20=0

We add all the numbers together, and all the variables

-8y+10=0

We move all terms containing y to the left, all other terms to the right

-8y=-10

y=-10/-8

y=1+1/4

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