-4(3y-2)-y=-4(y-3)

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Solution for -4(3y-2)-y=-4(y-3) equation: 



-4(3y-2)-y=-4(y-3)

We move all terms to the left:

-4(3y-2)-y-(-4(y-3))=0

We add all the numbers together, and all the variables

-1y-4(3y-2)-(-4(y-3))=0

We multiply parentheses

-1y-12y-(-4(y-3))+8=0



We calculate terms in parentheses: -(-4(y-3)), so:

-4(y-3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)



We add all the numbers together, and all the variables

-13y-(-4y+12)+8=0

We get rid of parentheses

-13y+4y-12+8=0

We add all the numbers together, and all the variables

-9y-4=0

We move all terms containing y to the left, all other terms to the right

-9y=4

y=4/-9

y=-4/9

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