-4(3x-2)=16x

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Solution for -4(3x-2)=16x equation: 



-4(3x-2)=16x

We move all terms to the left:

-4(3x-2)-(16x)=0

We add all the numbers together, and all the variables

-16x-4(3x-2)=0

We multiply parentheses

-16x-12x+8=0

We add all the numbers together, and all the variables

-28x+8=0

We move all terms containing x to the left, all other terms to the right

-28x=-8

x=-8/-28

x=2/7

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