-4(3x+2)=40+6x

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Solution for -4(3x+2)=40+6x equation: 



-4(3x+2)=40+6x

We move all terms to the left:

-4(3x+2)-(40+6x)=0

We add all the numbers together, and all the variables

-4(3x+2)-(6x+40)=0

We multiply parentheses

-12x-(6x+40)-8=0

We get rid of parentheses

-12x-6x-40-8=0

We add all the numbers together, and all the variables

-18x-48=0

We move all terms containing x to the left, all other terms to the right

-18x=48

x=48/-18

x=-2+2/3

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