-4(3b+3)+(13b-5)=0

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Solution for -4(3b+3)+(13b-5)=0 equation:


Simplifying
-4(3b + 3) + (13b + -5) = 0

Reorder the terms:
-4(3 + 3b) + (13b + -5) = 0
(3 * -4 + 3b * -4) + (13b + -5) = 0
(-12 + -12b) + (13b + -5) = 0

Reorder the terms:
-12 + -12b + (-5 + 13b) = 0

Remove parenthesis around (-5 + 13b)
-12 + -12b + -5 + 13b = 0

Reorder the terms:
-12 + -5 + -12b + 13b = 0

Combine like terms: -12 + -5 = -17
-17 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-17 + 1b = 0

Solving
-17 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 1b = 0 + 17

Combine like terms: -17 + 17 = 0
0 + 1b = 0 + 17
1b = 0 + 17

Combine like terms: 0 + 17 = 17
1b = 17

Divide each side by '1'.
b = 17

Simplifying
b = 17

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