-4(3b+2)+(13b-3)=0

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Solution for -4(3b+2)+(13b-3)=0 equation:


Simplifying
-4(3b + 2) + (13b + -3) = 0

Reorder the terms:
-4(2 + 3b) + (13b + -3) = 0
(2 * -4 + 3b * -4) + (13b + -3) = 0
(-8 + -12b) + (13b + -3) = 0

Reorder the terms:
-8 + -12b + (-3 + 13b) = 0

Remove parenthesis around (-3 + 13b)
-8 + -12b + -3 + 13b = 0

Reorder the terms:
-8 + -3 + -12b + 13b = 0

Combine like terms: -8 + -3 = -11
-11 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-11 + 1b = 0

Solving
-11 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1b = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 1b = 0 + 11
1b = 0 + 11

Combine like terms: 0 + 11 = 11
1b = 11

Divide each side by '1'.
b = 11

Simplifying
b = 11

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