-4(3b+1)+(13b-1)=0

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Solution for -4(3b+1)+(13b-1)=0 equation:


Simplifying
-4(3b + 1) + (13b + -1) = 0

Reorder the terms:
-4(1 + 3b) + (13b + -1) = 0
(1 * -4 + 3b * -4) + (13b + -1) = 0
(-4 + -12b) + (13b + -1) = 0

Reorder the terms:
-4 + -12b + (-1 + 13b) = 0

Remove parenthesis around (-1 + 13b)
-4 + -12b + -1 + 13b = 0

Reorder the terms:
-4 + -1 + -12b + 13b = 0

Combine like terms: -4 + -1 = -5
-5 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-5 + 1b = 0

Solving
-5 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1b = 0 + 5
1b = 0 + 5

Combine like terms: 0 + 5 = 5
1b = 5

Divide each side by '1'.
b = 5

Simplifying
b = 5

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