-4(3Y+3)=3(5-4Y)-27

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Solution for -4(3Y+3)=3(5-4Y)-27 equation: 


Simplifying
-4(3Y + 3) = 3(5 + -4Y) + -27

Reorder the terms:
-4(3 + 3Y) = 3(5 + -4Y) + -27
(3 * -4 + 3Y * -4) = 3(5 + -4Y) + -27
(-12 + -12Y) = 3(5 + -4Y) + -27
-12 + -12Y = (5 * 3 + -4Y * 3) + -27
-12 + -12Y = (15 + -12Y) + -27

Reorder the terms:
-12 + -12Y = 15 + -27 + -12Y

Combine like terms: 15 + -27 = -12
-12 + -12Y = -12 + -12Y

Add '12' to each side of the equation.
-12 + 12 + -12Y = -12 + 12 + -12Y

Combine like terms: -12 + 12 = 0
0 + -12Y = -12 + 12 + -12Y
-12Y = -12 + 12 + -12Y

Combine like terms: -12 + 12 = 0
-12Y = 0 + -12Y
-12Y = -12Y

Add '12Y' to each side of the equation.
-12Y + 12Y = -12Y + 12Y

Combine like terms: -12Y + 12Y = 0
0 = -12Y + 12Y

Combine like terms: -12Y + 12Y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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