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-4(3-x)=4/5(x+5)
We move all terms to the left:
-4(3-x)-(4/5(x+5))=0
Domain of the equation: 5(x+5))!=0We add all the numbers together, and all the variables
x∈R
-4(-1x+3)-(4/5(x+5))=0
We multiply parentheses
4x-(4/5(x+5))-12=0
We multiply all the terms by the denominator
4x*5(x+5))-(4-12*5(x+5))=0
Wy multiply elements
20x^2(x-60x(x=0
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