-4(3-x)=16-2(x-1)

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Solution for -4(3-x)=16-2(x-1) equation: 



-4(3-x)=16-2(x-1)

We move all terms to the left:

-4(3-x)-(16-2(x-1))=0

We add all the numbers together, and all the variables

-4(-1x+3)-(16-2(x-1))=0

We multiply parentheses

4x-(16-2(x-1))-12=0



We calculate terms in parentheses: -(16-2(x-1)), so:

16-2(x-1)

determiningTheFunctionDomain
-2(x-1)+16

We multiply parentheses

-2x+2+16

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We get rid of parentheses

4x+2x-18-12=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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