-4(2z+5)+5z-1=-48

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Solution for -4(2z+5)+5z-1=-48 equation: 



-4(2z+5)+5z-1=-48

We move all terms to the left:

-4(2z+5)+5z-1-(-48)=0

We add all the numbers together, and all the variables

5z-4(2z+5)+47=0

We multiply parentheses

5z-8z-20+47=0

We add all the numbers together, and all the variables

-3z+27=0

We move all terms containing z to the left, all other terms to the right

-3z=-27

z=-27/-3

z=+9

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